UPSC CSAT Quiz – 2021: IASbaba’s Daily CSAT Practice Test – 20th January 2021
 Posted by IASbaba
 Categories IASbaba’s Daily CSAT Practice Test
 Date January 20, 2021
 Comments 0 comment
[New Batch] IASbaba’s Courses UPSC 2021 : eCLP, ILP, AIPTS, TLP Connect ADMISSIONS OPEN! > Click Here
ARCHIVES
Daily CSAT Practice Test
Everyday 5 Questions from Aptitude, Logical Reasoning, and Reading Comprehension will be covered from Monday to Saturday.
Make the best use of the initiative. All the best!
To Know More about Ace the Prelims (ATP) 2021 – CLICK HERE
Important Note:
 Don’t forget to post your marks in the comment section. Also, let us know if you enjoyed today’s test 🙂
 After completing the 5 questions, click on ‘View Questions’ to check your score, time taken and solutions.
Testsummary
0 of 5 questions completed
Questions:
 1
 2
 3
 4
 5
Information
To view Solutions, follow these instructions:
 Click on – ‘Start Test’ button
 Solve Questions
 Click on ‘Test Summary’ button
 Click on ‘Finish Test’ button
 Now click on ‘View Questions’ button – here you will see solutions and links.
You have already completed the test before. Hence you can not start it again.
Test is loading...
You must sign in or sign up to start the test.
You have to finish following test, to start this test:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have scored 0 points out of 0 points, (0)
Average score 

Your score 

Categories
 Not categorized 0%
Pos.  Name  Entered on  Points  Result 

Table is loading  
No data available  
 1
 2
 3
 4
 5
 Answered
 Review

Question 1 of 5
1. Question
A train sets off at 3 pm at the speed of 70 kmph. Another train starts at 4.30 pm in the same direction at the rate of 85 kmph. At what time they will meet?
Correct
Solution (c)
B ———————————A
105 km
The time gap between the two train is 1.5 hours which means by the time train B sets off the train A would be 105 km ahead of train B (speed of train A is 70 kmph)
Since both the trains are moving in the same direction, as per the relative speed concept
The speed of the trains will be subtracted i.e. 85 – 70 = 15 kmph
To meet the train A, train B will have to cover 105 km with 15 kmph speed
Therefore both the trains will meet after 105/15 = 7 hours
i.e. 4.30 pm + 7 hours = 11.30 pm
Incorrect
Solution (c)
B ———————————A
105 km
The time gap between the two train is 1.5 hours which means by the time train B sets off the train A would be 105 km ahead of train B (speed of train A is 70 kmph)
Since both the trains are moving in the same direction, as per the relative speed concept
The speed of the trains will be subtracted i.e. 85 – 70 = 15 kmph
To meet the train A, train B will have to cover 105 km with 15 kmph speed
Therefore both the trains will meet after 105/15 = 7 hours
i.e. 4.30 pm + 7 hours = 11.30 pm

Question 2 of 5
2. Question
A and B are two alloys of copper and zinc prepared by mixing metals in the ratio 7:2 and 7:11 respectively. If equal quantities of A and B are melted to form third alloy C then the ratio of zinc and copper in C is
Correct
Solution (b)
Weight of Alloy A is 9 units and weight of alloy B is 18 units
In order to mix equal quantity of metals their weight should be same
So, we need to double the weight of alloy A i.e. 14:4
Now alloy A = 14:4
Alloy B = 7:11
If we mix both the alloys the ratio becomes 21:15 = 7:5
Therefore the ratio of copper and zinc in alloy C is 7:5 > Zinc & Copper is 5:7.
Incorrect
Solution (b)
Weight of Alloy A is 9 units and weight of alloy B is 18 units
In order to mix equal quantity of metals their weight should be same
So, we need to double the weight of alloy A i.e. 14:4
Now alloy A = 14:4
Alloy B = 7:11
If we mix both the alloys the ratio becomes 21:15 = 7:5
Therefore the ratio of copper and zinc in alloy C is 7:5 > Zinc & Copper is 5:7.

Question 3 of 5
3. Question
Read the following passage and answer the questions that follow each passage. Your answer to these questions should be based on passage only.
Marcia says that all of her friends have a cell phone, but Marcia’s mom doesn’t want to buy her one. Marcia’s mom doesn’t want Marcia to play video games either. What is more, the Internet scares her. Marcia’s mom says, “If Marcia has a cell phone, how do we know whom she is talking to? Video games are bad for you. The Internet is dangerous and uncontrolled. It’s like having a gun in the house. We should just ban her from using the computer, and I’m not buying her a cell phone until she is eighteen. This is the only way we can be sure that Marcia is safe.”
Marcia’s dad disagrees with Marcia’s mom. Although he agrees that there are some dangers to it, he likes the Internet, and finds it to be very useful. “The trouble is,” he says, “We just can’t stop Marcia from using the Internet, as this would put her at a disadvantage. What is more, I like video games. I think that, when played in moderation, they are fun. Obviously, it is not good to play them without restraint or selfcontrol. Finally, I think Marcia needs a cell phone. We can’t take these things away.”
In paragraph 1, Marcia’s mom says, “It’s like having a gun in the house.” She says this in order to
Correct
Solution (a)
To answer this question, it helps to use context. In paragraph 1, Mom says “The Internet is dangerous and uncontrolled. It’s like having a gun in the house.” Since Mom says that the Internet is dangerous immediately before she compares it to having a gun in the house, we can understand that Mom draws this comparison to illustrate how dangerous she thinks the Internet is. This makes (A) the correct choice. Mom is not arguing that guns can never be safe. Rather, she compares the Internet to guns to express how dangerous she finds the Internet. This makes (B) incorrect. Mom does not encourage Dad to buy a gun, so (C) is not the best choice. Mom compares having the Internet to having a gun in the house. She does this to explain how dangerous the internet is, not explain why the Internet is uncontrolled. This rules out (D).
Incorrect
Solution (a)
To answer this question, it helps to use context. In paragraph 1, Mom says “The Internet is dangerous and uncontrolled. It’s like having a gun in the house.” Since Mom says that the Internet is dangerous immediately before she compares it to having a gun in the house, we can understand that Mom draws this comparison to illustrate how dangerous she thinks the Internet is. This makes (A) the correct choice. Mom is not arguing that guns can never be safe. Rather, she compares the Internet to guns to express how dangerous she finds the Internet. This makes (B) incorrect. Mom does not encourage Dad to buy a gun, so (C) is not the best choice. Mom compares having the Internet to having a gun in the house. She does this to explain how dangerous the internet is, not explain why the Internet is uncontrolled. This rules out (D).

Question 4 of 5
4. Question
Ankush and Bharath work in a shop and Ankush’s salary is 5/6th of the salary of Bharath. They spend same money of Rs 2000 and after that save all the money. Find the salary of Ankush and Bharath if the ratio of their savings is 4:5.
Correct
Solution (a)
Let Bharath’s salary = Rs x
Ankush’s salary = Rs 5x/ 6
According to the question,
5x/ 6 – 2000: x – 2000 = 4 : 5
5 (5x/ 6 – 2000) = 4 (x – 2000)
25x/ 6 – 10000 = 4x – 8000
25x/ 6 – 4x = 10000 – 8000
X / 6 = 2000
x = 12000
Ankush’s salary = Rs 10,000, Bharath’s salary = Rs 12,000
Incorrect
Solution (a)
Let Bharath’s salary = Rs x
Ankush’s salary = Rs 5x/ 6
According to the question,
5x/ 6 – 2000: x – 2000 = 4 : 5
5 (5x/ 6 – 2000) = 4 (x – 2000)
25x/ 6 – 10000 = 4x – 8000
25x/ 6 – 4x = 10000 – 8000
X / 6 = 2000
x = 12000
Ankush’s salary = Rs 10,000, Bharath’s salary = Rs 12,000

Question 5 of 5
5. Question
A rectangular block 6 cm by 12 cm by 15 cm is cut up in to an exact number of equal cubes. Find the least possible number of cubes.
Correct
Solution (d)
Volume of the block = (6 × 12 × 15) cm3 = 1080 cm3.
Side of the largest cube = H.C.F. of 6 cm, 12 cm, 15 cm = 3 cm.
Volume of this cube = (3 × 3 × 3) cm3 27 cm3
∴ Number of cubes = (1080/27) = 40
Incorrect
Solution (d)
Volume of the block = (6 × 12 × 15) cm3 = 1080 cm3.
Side of the largest cube = H.C.F. of 6 cm, 12 cm, 15 cm = 3 cm.
Volume of this cube = (3 × 3 × 3) cm3 27 cm3
∴ Number of cubes = (1080/27) = 40