IASbaba’s Daily CSAT Practice Test
ARCHIVES
Daily CSAT Practice Test
Everyday 5 Questions from Aptitude, Logical Reasoning, and Reading Comprehension will be covered from Monday to Saturday.
Make the best use of the initiative. All the best!
To Know More about Ace the Prelims (ATP) 2021 – CLICK HERE
Important Note:
- Don’t forget to post your marks in the comment section. Also, let us know if you enjoyed today’s test 🙂
- After completing the 5 questions, click on ‘View Questions’ to check your score, time taken and solutions.
Test-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
To view Solutions, follow these instructions:
- Click on – ‘Start Test’ button
- Solve Questions
- Click on ‘Test Summary’ button
- Click on ‘Finish Test’ button
- Now click on ‘View Questions’ button – here you will see solutions and links.
You have already completed the test before. Hence you can not start it again.
Test is loading...
You must sign in or sign up to start the test.
You have to finish following test, to start this test:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have scored 0 points out of 0 points, (0)
Average score |
|
Your score |
|
Categories
- Not categorized 0%
Pos. | Name | Entered on | Points | Result |
---|---|---|---|---|
Table is loading | ||||
No data available | ||||
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?
Correct
Solution (d)
We have: l = 20 ft. and lb = 680 sq ft.
So, b = 34 ft.
Length of fencing = (l + 2b) = (20 + 68) ft. = 88 ft.
Incorrect
Solution (d)
We have: l = 20 ft. and lb = 680 sq ft.
So, b = 34 ft.
Length of fencing = (l + 2b) = (20 + 68) ft. = 88 ft.
-
Question 2 of 5
2. Question
Prema is twice as efficient as Anjali and takes 90 days less than Anjali to complete the job. Find the time in which they can finish the job together?
Correct
Solution (d)
Since ‘A’ is ‘m’ times as efficient as ‘B’ & takes ‘D’ days less than ‘B’, then the time required to complete the job together is given by,
T = m × D / (m2-1)
T = 2 × 90 / (4-1)
T = 60 days
Incorrect
Solution (d)
Since ‘A’ is ‘m’ times as efficient as ‘B’ & takes ‘D’ days less than ‘B’, then the time required to complete the job together is given by,
T = m × D / (m2-1)
T = 2 × 90 / (4-1)
T = 60 days
-
Question 3 of 5
3. Question
A sales executive went to meet his client A in another office 17 km away in the North-east direction of his own office. From there he went to see client B in an office 15 km in the south of his client A’s office. How far from the starting point and in what direction is he now?
Correct
Solution (b)
Incorrect
Solution (b)
-
Question 4 of 5
4. Question
Given below are the statement and 2 conclusions. Based on that select the correct option
Statement: T ≤ M ≤ J = Q > F > S; M > R
Conclusions:
- Q ≥ T
- J > S
Choose the correct code
Correct
Solution (c)
T ≤ M ≤ J = Q > F > Sà(1)
M > R à(2)
From (1), we get
T ≤ Q or Q ≥ T. Thus, conclusion I is true
Again, J > S is true. Hence both conclusion I and II are true.
Incorrect
Solution (c)
T ≤ M ≤ J = Q > F > Sà(1)
M > R à(2)
From (1), we get
T ≤ Q or Q ≥ T. Thus, conclusion I is true
Again, J > S is true. Hence both conclusion I and II are true.
-
Question 5 of 5
5. Question
Given below are the statement and 2 conclusions. Based on that select the correct option
Statement: H > S ≥ F = B ≤ U ≤ T; E ≤ B ≤ K
Conclusions:
- U ≥ E
- S > T
Choose the correct code
Correct
Solution (a)
H > S ≥ F = B ≤ U ≤ Tà(1)
E ≤ B ≤ Kà(2)
Combining (1) and (2), we get
E ≤ B ≤ U
Thus, E ≤ U or U ≥ E. Hence I is true. Again we can’t compare S and T. Hence II (S > T) is not true.
Incorrect
Solution (a)
H > S ≥ F = B ≤ U ≤ Tà(1)
E ≤ B ≤ Kà(2)
Combining (1) and (2), we get
E ≤ B ≤ U
Thus, E ≤ U or U ≥ E. Hence I is true. Again we can’t compare S and T. Hence II (S > T) is not true.