IASbaba’s Daily CSAT Practice Test
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Daily CSAT Practice Test
Everyday 5 Questions from Aptitude, Logical Reasoning, and Reading Comprehension will be covered from Monday to Saturday.
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Question 1 of 5
1. Question
In an examination, 1100 boys and 900 girls appeared, 40% of the boys and 50% of the girls passed the examination. The percentage of candidates who failed is
Correct
Q.1) Solution (d)
Given, Number of boys = 1100
Number of girls = 900
Total candidates = 2000
Now, according to the question,
Number of failed candidates = 1100*(100 – 40)/100 + 900*(100 – 50)/100 = 660+450 = 1110
Therefore, the percentage of students who failed = (failed candidates/Total candidates)*100 = (1110/2000)*100 = 55.5%
Incorrect
Q.1) Solution (d)
Given, Number of boys = 1100
Number of girls = 900
Total candidates = 2000
Now, according to the question,
Number of failed candidates = 1100*(100 – 40)/100 + 900*(100 – 50)/100 = 660+450 = 1110
Therefore, the percentage of students who failed = (failed candidates/Total candidates)*100 = (1110/2000)*100 = 55.5%
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Question 2 of 5
2. Question
Arjun’s expense is 50% more than Vijay’s expense and Vijay’s expense is 20% less than Rohan’s expense. If the sum of their expenses is Rs 6540, then what would be the Arjun’s expense?
Correct
Q.2) Solution (d)
Let Rohan’s expense be P
Expense of Vijay’s = 0.8P
Expense of Arjun’s = 1.5×0.8P=1.2P
Hence 3P=6540
P = 2180 Rs
Arjun’s expense = 1.2×2180 = 2616 Rs
Incorrect
Q.2) Solution (d)
Let Rohan’s expense be P
Expense of Vijay’s = 0.8P
Expense of Arjun’s = 1.5×0.8P=1.2P
Hence 3P=6540
P = 2180 Rs
Arjun’s expense = 1.2×2180 = 2616 Rs
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Question 3 of 5
3. Question
Ratio of the number of sides of two regular polygons is 5: 6 and the ratio of their each interior angle is 24: 25. Then the number of sides of these two polygons are
Correct
Q.3) Solution (a)
Let the number of sides of two polygons be 5X and 6X
Thus, 180(5X-2)/5X = 24/25
180(6X-2)/6X
X = 2
Thus the sides are (10, 12)
Incorrect
Q.3) Solution (a)
Let the number of sides of two polygons be 5X and 6X
Thus, 180(5X-2)/5X = 24/25
180(6X-2)/6X
X = 2
Thus the sides are (10, 12)
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Question 4 of 5
4. Question
Two trains start from stations A and B and travel towards each other at speeds of 50 km/hour and 60 km/hour respectively. At the time of their meeting, the second train has travelled 120 km more than the first. The distance between A and B is
Correct
Q.4) Solution (c)
The speed of B is 10 Km/hr more than A.
Therefore the difference of 120 km must have been created in = 120/10 = 12 hrs.
The relative speed = 110 Km/hr
The total distance is 110 km/hr X 12 = 1320 Km
Incorrect
Q.4) Solution (c)
The speed of B is 10 Km/hr more than A.
Therefore the difference of 120 km must have been created in = 120/10 = 12 hrs.
The relative speed = 110 Km/hr
The total distance is 110 km/hr X 12 = 1320 Km
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Question 5 of 5
5. Question
The average age of a group is increased by 6 years when a person of whose age is 35 years was replaced by a person whose age is 71. Find the number of persons in the group?
Correct
Q.5) Solution (c)
Let the number of members = n and average = a
Total age will be = na
Now increase in average = 6 years
Therefore total new age = n (a + 6)
Now, na – 35 + 71 = na +6n
na + 36 = na + 6n = 6
Incorrect
Q.5) Solution (c)
Let the number of members = n and average = a
Total age will be = na
Now increase in average = 6 years
Therefore total new age = n (a + 6)
Now, na – 35 + 71 = na +6n
na + 36 = na + 6n = 6
