IASbaba’s Daily CSAT Practice Test
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Daily CSAT Practice Test
Everyday 5 Questions from Aptitude, Logical Reasoning, and Reading Comprehension will be covered from Monday to Saturday.
Make the best use of the initiative. All the best!
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Question 1 of 5
1. Question
In a parking basement of a company, there are some bicycles and cars. On Tuesday there are 182 wheels in the basement. How many bicycles are there?
Correct
Solution (b)
Check using the options
If there are 20 bicycles, there must be 20*2 = 40 wheels
Remaining wheels = 182-40 = 142 wheels = 142/4 is not an integer so there cannot be 20 bicycles.
Similarly checking for 19 bicycles = 19*2 = 38 wheels
Remaining wheels = 182 – 38 = 144 = 144/4 = 36 cars hence this is the answer.
Incorrect
Solution (b)
Check using the options
If there are 20 bicycles, there must be 20*2 = 40 wheels
Remaining wheels = 182-40 = 142 wheels = 142/4 is not an integer so there cannot be 20 bicycles.
Similarly checking for 19 bicycles = 19*2 = 38 wheels
Remaining wheels = 182 – 38 = 144 = 144/4 = 36 cars hence this is the answer.
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Question 2 of 5
2. Question
One-third phenol is taken out from the bottle of phenol and then an equal amount of water is poured into the bottle to fill it. This operation is done three times. Find the final ratio of phenol and water in the bottle?
Correct
Solution (b)
After the first operation, the amount of Dettol in the bottle = 2/3
After the second operation, the amount of Dettol in the bottle = 2/3 x 2/3 = 4/9
After the third operation, the amount of Dettol in the bottle = 4/9 x 2/3 = 8/27
The amount of water after the forth operation = 1 – 8/27 = 19/27
Therefore the required ratio = 8/27 : 19/27 = 8 : 19
Incorrect
Solution (b)
After the first operation, the amount of Dettol in the bottle = 2/3
After the second operation, the amount of Dettol in the bottle = 2/3 x 2/3 = 4/9
After the third operation, the amount of Dettol in the bottle = 4/9 x 2/3 = 8/27
The amount of water after the forth operation = 1 – 8/27 = 19/27
Therefore the required ratio = 8/27 : 19/27 = 8 : 19
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Question 3 of 5
3. Question
Alok is thrice as good a workman as Nandu and is therefore able to finish a piece of work in 60 days less than Nandu. Find the time in which they can do it working together
Correct
Solution (b)
Let us assume that the work done by Alok = w days
So the time taken by Nandu = 3w
So according to the question
3w – w = 60
W = 30 day
And 3w = 90 days
Therefore together they can finish the work in {(30 x 90)/(30 + 90)} = 22.5 days
Incorrect
Solution (b)
Let us assume that the work done by Alok = w days
So the time taken by Nandu = 3w
So according to the question
3w – w = 60
W = 30 day
And 3w = 90 days
Therefore together they can finish the work in {(30 x 90)/(30 + 90)} = 22.5 days
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Question 4 of 5
4. Question
RJPL : NNLP : : YAWC : ?
Correct
Solution (c)
The 1st & 3rd letters of the 1st group are each moved four steps backward to obtain the corresponding letters of the 2nd group. The 2nd and 4th letters of the 1st group are each moved 4 steps forward to obtain the corresponding letters of the 2nd group.
Similar relationship will exist between the 3rd and the 4th groups.
Incorrect
Solution (c)
The 1st & 3rd letters of the 1st group are each moved four steps backward to obtain the corresponding letters of the 2nd group. The 2nd and 4th letters of the 1st group are each moved 4 steps forward to obtain the corresponding letters of the 2nd group.
Similar relationship will exist between the 3rd and the 4th groups.
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Question 5 of 5
5. Question
Find the wrong number from the given series
11 14 20 29 40 56
Correct
Solution (d)
Logic is that first difference is 3, next difference is 6, 9, so next should be 12 & 15. So instead of 40 the term should be 41
Incorrect
Solution (d)
Logic is that first difference is 3, next difference is 6, 9, so next should be 12 & 15. So instead of 40 the term should be 41
