UPSC CSAT Quiz – 2021: IASbaba’s Daily CSAT Practice Test – 27th January 2021
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 Date January 27, 2021
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Daily CSAT Practice Test
Everyday 5 Questions from Aptitude, Logical Reasoning, and Reading Comprehension will be covered from Monday to Saturday.
Make the best use of the initiative. All the best!
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Question 1 of 5
1. Question
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is
Correct
Solution (b)
Let C.P. of each article be Re. 1 C.P. of x articles = Rs X
S.P. of x articles = Rs 20.
Profit = Rs (20 – x)
[(20x)/x]*100 = 25
2000 – 100x = 25x
125x = 2000
x = 16
Incorrect
Solution (b)
Let C.P. of each article be Re. 1 C.P. of x articles = Rs X
S.P. of x articles = Rs 20.
Profit = Rs (20 – x)
[(20x)/x]*100 = 25
2000 – 100x = 25x
125x = 2000
x = 16

Question 2 of 5
2. Question
In a mixture of 13 litres, the ratio of milk and water is 3:2. If 3 litres of this mixture is replaced by 3 litres of milk, then what will be the ratio of milk and water in the newly formed mixture?
Correct
Solution (c)
Total quantity of mixture = 13 litres
3 litres of mixture is removed from the container – So, let’s forget this altogether!
Now, you are left with only 10 litres of mixture in 3:2 ratios.
Milk in 10 litres mix = (10 x3) / (2=3) = 6 litres
Water in 10 litres mix = (10 x2) / (2+3) = 4 litres
We add 3 litres milk to this.
So, milk in new mixture = 6+3 = 9 litres
Water = 4 litres
Incorrect
Solution (c)
Total quantity of mixture = 13 litres
3 litres of mixture is removed from the container – So, let’s forget this altogether!
Now, you are left with only 10 litres of mixture in 3:2 ratios.
Milk in 10 litres mix = (10 x3) / (2=3) = 6 litres
Water in 10 litres mix = (10 x2) / (2+3) = 4 litres
We add 3 litres milk to this.
So, milk in new mixture = 6+3 = 9 litres
Water = 4 litres

Question 3 of 5
3. Question
Read the following passage and answer the question that follows the passage.
The New Year is a time for resolutions. Mentally at least, most of us could compile formidable lists of do’s and don’ts. The same old favourites recur year in and year out with monotonous regularity. Past experience has taught us that certain accomplishments are beyond attainment
If we remain inveterate smokers, it is only because we have so often experienced the frustration that results from failure. Most of us fail in our efforts at selfimprovement because our schemes are too ambitious and we never have time to carry them out.
We also make the fundamental error of announcing our resolutions to everybody so that we look even more foolish when we slip back into our old bad ways.
The phrase ‘formidable lists of do’s and don’ts mean that
Correct
Solution (b)
Selfexplanatory
Incorrect
Solution (b)
Selfexplanatory

Question 4 of 5
4. Question
Two pipes can fill a tank in 10 and 14 minutes respectively and a waste pipe can empty 4 gallons per minute. If all the pipes working together can fill the tank in 6 minutes, what is the capacity of the tank?
Correct
Solution (d)
Work done by waste pipe in 1 min = (Part filled by total pipes together) – (part filled by first pipe + part filled by second pipe)
= 1/6 – [(1/10) + (1/14)] = 1/6 – (24/140) = 1/210
Here, negative () sign indicates emptying of tank.
To find the capacity, we need to determine the volume of 1/210 part.
Therefore, volume of 1/210 part = 4 gallons à(given condition)
Hence, the capacity of tank = volume of whole = 4 x 210 = 840 gallons.
Incorrect
Solution (d)
Work done by waste pipe in 1 min = (Part filled by total pipes together) – (part filled by first pipe + part filled by second pipe)
= 1/6 – [(1/10) + (1/14)] = 1/6 – (24/140) = 1/210
Here, negative () sign indicates emptying of tank.
To find the capacity, we need to determine the volume of 1/210 part.
Therefore, volume of 1/210 part = 4 gallons à(given condition)
Hence, the capacity of tank = volume of whole = 4 x 210 = 840 gallons.

Question 5 of 5
5. Question
One year ago, ratio of ages of Harish and Pratap was 5:6 respectively. After 4 years, this ratio becomes 6:7. How old is Pratap?
Correct
Solution (c)
We are given that age ratio of Harish: Pratap = 5:6
Harish’s age = 5x and Pratap’s age = 6x
One year ago, their age was 5x and 6x. Hence at present, Harish’s age = 5x +1 and Pratap’s age = 6x +1
After 4 years,
Incorrect
Solution (c)
We are given that age ratio of Harish: Pratap = 5:6
Harish’s age = 5x and Pratap’s age = 6x
One year ago, their age was 5x and 6x. Hence at present, Harish’s age = 5x +1 and Pratap’s age = 6x +1
After 4 years,