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Daily CSAT Practice Test
Everyday 5 Questions from Aptitude, Logical Reasoning, and Reading Comprehension will be covered from Monday to Saturday.
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Question 1 of 5
1. Question
Mother is aged three times more than his daughter Sona. After 8 years she would be two and half times of Sona’s age. After further 8 years, how many times would she be of Sona’s age?
Correct
Solution (a)
Let the present age of Sona be ‘x’ years,
Then her mother’s present age = (x+3x) = 4x years
Therefore, (4x+8) = 5/2(x+8)
8x + 16 = 5x + 40
3x = 24
X=8
Hence, required ratio= (4x+16)/(x+16) = 2
Incorrect
Solution (a)
Let the present age of Sona be ‘x’ years,
Then her mother’s present age = (x+3x) = 4x years
Therefore, (4x+8) = 5/2(x+8)
8x + 16 = 5x + 40
3x = 24
X=8
Hence, required ratio= (4x+16)/(x+16) = 2

Question 2 of 5
2. Question
The sum of four consecutive even numbers is 284. What would be the smallest number?
Correct
Solution (b)
Let four consecutive even numbers be X, X+2, X+4, X+6
According to the question,
X+X+2+X+4+X+6=284
4X+12=284
X=68
Incorrect
Solution (b)
Let four consecutive even numbers be X, X+2, X+4, X+6
According to the question,
X+X+2+X+4+X+6=284
4X+12=284
X=68

Question 3 of 5
3. Question
When 1/7 of a number is subtracted from the number itself, it gives the same value as the sum of all the angles of a triangle. What is the number?
Correct
Solution (a)
Let the number be X
As per the question,
XX/7=180(sum of all angles of a triangle)
6X/7=180
X=210
Incorrect
Solution (a)
Let the number be X
As per the question,
XX/7=180(sum of all angles of a triangle)
6X/7=180
X=210

Question 4 of 5
4. Question
Arjun has invested a sum of 1,200 Rs in the shares of a company, in what time his investment will become 1,450 Rs when annual rate of interest is 20%?
Correct
Solution (a)
Here P=1,200 Rs, A=1,450 Rs, R=20%
We know that, A=P+SI
1,450=1,200+SI
SI=250
Again, SI = (P*R*T)/100
250 = 1,200*20*T/100
T=25/24=1 (1/24) yrs
Incorrect
Solution (a)
Here P=1,200 Rs, A=1,450 Rs, R=20%
We know that, A=P+SI
1,450=1,200+SI
SI=250
Again, SI = (P*R*T)/100
250 = 1,200*20*T/100
T=25/24=1 (1/24) yrs

Question 5 of 5
5. Question
If a pipe can fill a tank in 2 hr and another pipe can fill the same tank in 6 hr, then what part of the tank will be filled by both the pipes in 2 hr, if they are opened simultaneously?
Correct
Solution (a)
Part of the tank filled by first pipe in 1 hr = 1/2
Similarly, Part of the tank filled by second pipe in 1 hr = 1/6
Part filled by pipes in 1 hr = 1/2+1/6
= 2/3
Again, Part filled by both the pipes in 2 hr = 4/3
Incorrect
Solution (a)
Part of the tank filled by first pipe in 1 hr = 1/2
Similarly, Part of the tank filled by second pipe in 1 hr = 1/6
Part filled by pipes in 1 hr = 1/2+1/6
= 2/3
Again, Part filled by both the pipes in 2 hr = 4/3
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