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Daily CSAT Practice Test
Everyday 5 Questions from Aptitude, Logical Reasoning, and Reading Comprehension will be covered from Monday to Saturday.
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Question 1 of 5
1. Question
A man sold an item for Rs.6750 at a loss of 25%. What will be the selling price of same item if he sells it at a profit of 15%?
Correct
Solution (b)
Let the cost price of the item be Rs.100 so the selling price will be Rs.75
When the Selling price is Rs.75 Cost price is Rs.100
When the Selling price will be Rs.1 then cost price will be Rs.(100/75)
When the selling price is Rs.6750 cost price should be Rs.(100/75)*6750 which is Rs.9000.
Now,
When cost price is Rs.100 selling price is Rs.115
When cost price is Rs.1, selling price will be Rs.(115/100)
So, if cost price Rs.9000 selling price is Rs.(115/100)*9000 = Rs.10,350
Incorrect
Solution (b)
Let the cost price of the item be Rs.100 so the selling price will be Rs.75
When the Selling price is Rs.75 Cost price is Rs.100
When the Selling price will be Rs.1 then cost price will be Rs.(100/75)
When the selling price is Rs.6750 cost price should be Rs.(100/75)*6750 which is Rs.9000.
Now,
When cost price is Rs.100 selling price is Rs.115
When cost price is Rs.1, selling price will be Rs.(115/100)
So, if cost price Rs.9000 selling price is Rs.(115/100)*9000 = Rs.10,350

Question 2 of 5
2. Question
Two students appeared in an examination. One of them secured 12 marks more than the other and his marks was 60% of the sum of their marks. The marks obtained by them are:
Correct
Solution (c)
Let their marks be (x + 12) and x
Then, x+12 = (60/100)* (x+x+12)
100x+1200 = 60(2x+12)
1200 720 = 120x100x
480 = 20x
x = 480/20 = 24
So, their marks are (24+12), 24 i.e., 24 & 36
Incorrect
Solution (c)
Let their marks be (x + 12) and x
Then, x+12 = (60/100)* (x+x+12)
100x+1200 = 60(2x+12)
1200 720 = 120x100x
480 = 20x
x = 480/20 = 24
So, their marks are (24+12), 24 i.e., 24 & 36

Question 3 of 5
3. Question
Read the following passage and answer the questions that follow. Your answer to these questions should be based on passage only.
Among young adults with a BMI between 25 and less than 40, the addition of a wearable technology device to a standard behavioral intervention resulted in less weight loss over 24 months. Devices that monitor and provide feedback on physical activity may not offer an advantage over standard behavioral weight loss approaches.
Assuming, it is normally believed that, wearable technology device has better results in case of weight loss efforts; does the passage comply with this given belief?
Correct
Solution (b)
It is clearly mentioned that the underlying assumption of improved performance with wearable technology is not correct.
Incorrect
Solution (b)
It is clearly mentioned that the underlying assumption of improved performance with wearable technology is not correct.

Question 4 of 5
4. Question
Read the following passage and answer the questions that follow. Your answer to these questions should be based on passage only.
Among young adults with a BMI between 25 and less than 40, the addition of a wearable technology device to a standard behavioral intervention resulted in less weight loss over 24 months. Devices that monitor and provide feedback on physical activity may not offer an advantage over standard behavioral weight loss approaches.
Being a rational person, which of the following do you think helps in weight loss program?
 Balanced diet
 Healthy routine
 Physical exercise
 Wearable Device
Which of the following is correct?
Correct
Solution (d)
All the components should be come together for the best possible outcome.
Incorrect
Solution (d)
All the components should be come together for the best possible outcome.

Question 5 of 5
5. Question
A man has ₹ 480 in the denominations of onerupee notes, fiverupee notes and tenrupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has?
Correct
Solution (d)
Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
16x = 480
x = 30.
Therefore, total number of notes = 3x = 90.
Incorrect
Solution (d)
Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
16x = 480
x = 30.
Therefore, total number of notes = 3x = 90.
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