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Daily CSAT Practice Test
Everyday 5 Questions from Aptitude, Logical Reasoning, and Reading Comprehension will be covered from Monday to Saturday.
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Question 1 of 5
1. Question
8% of voters in an election did not cast their votes. In this election there were only two candidates. The winner, by obtaining 48% of the total votes defeated his rival 1100 votes. The total number of voters in the election were
Correct
Solution (d)
Let the total voters be 100
Voters who didn’t cast their vote = 8
Votes given = 1008 = 92
Votes Obtained by Winner = 48% of the total = 48
Therefore, votes obtained by defeater = 44
So, when the difference is 4, total vote is 100
When the difference will be 1 total vote will be is 100/4
When the difference is 1100, total vote must have been (100/4)*1100 = 27,500
Incorrect
Solution (d)
Let the total voters be 100
Voters who didn’t cast their vote = 8
Votes given = 1008 = 92
Votes Obtained by Winner = 48% of the total = 48
Therefore, votes obtained by defeater = 44
So, when the difference is 4, total vote is 100
When the difference will be 1 total vote will be is 100/4
When the difference is 1100, total vote must have been (100/4)*1100 = 27,500

Question 2 of 5
2. Question
In a town, each of the 60% of families has a laptop, each of the 30% of families has a computer and each of the 15% of families has both a laptop and a computer. In all, there are 10800 families in the town. How many families in the town do not have a laptop or a computer?
Correct
Solution (d)
According to the concept of set theory, we know that n (a U b) = n (a) +n (b) – n (a ∩ b)
So, the % of families having either a laptop or a computer or both
== n (computer U laptop) = n (computer) +n(laptop) –n (computer and laptop)
== 60+30 15 = 75%
Families having neither a laptop nor a computer = 100 – 75 = 25%
So, required family = 25/100 x 10800 = 2700
Incorrect
Solution (d)
According to the concept of set theory, we know that n (a U b) = n (a) +n (b) – n (a ∩ b)
So, the % of families having either a laptop or a computer or both
== n (computer U laptop) = n (computer) +n(laptop) –n (computer and laptop)
== 60+30 15 = 75%
Families having neither a laptop nor a computer = 100 – 75 = 25%
So, required family = 25/100 x 10800 = 2700

Question 3 of 5
3. Question
There are two examinations rooms A and B. If 20 students are sent from A to B, then the number of students in each room is the same. If 10 candidates are sent from B to A, then the number of students in A is three times the number of students in B. The number of students in room A is:
Correct
Solution (b)
Let the number of students in rooms A and B be x and y respectively.
A/Q,
x – 20 =y + 20 which gives x =y + 40 ……………………………… (i)
And x+10 = 3(y10) which gives x = 3y 40……………………….. (ii)
Equating (i) & (ii) we get,
40 + y = 3y 40
2y = 80
y = 40
Putting the value of y =40 in equation (i) we get, x = 80
Incorrect
Solution (b)
Let the number of students in rooms A and B be x and y respectively.
A/Q,
x – 20 =y + 20 which gives x =y + 40 ……………………………… (i)
And x+10 = 3(y10) which gives x = 3y 40……………………….. (ii)
Equating (i) & (ii) we get,
40 + y = 3y 40
2y = 80
y = 40
Putting the value of y =40 in equation (i) we get, x = 80

Question 4 of 5
4. Question
Distance between two places is 35 km. If two persons start running towards each other from these two places with the speed of 3 km/h and 4 km/h. at 7 AM. At what time do they meet?
Correct
Solution (d)
As they are running towards each other, the relative speed will be = (3+4) km/hr = 7 km/hr So, time taken to cover distance of 35kms = Distance /Speed = 35kms/7kmph = 5hrs
Therefore, they will meet at 12pm.
Incorrect
Solution (d)
As they are running towards each other, the relative speed will be = (3+4) km/hr = 7 km/hr So, time taken to cover distance of 35kms = Distance /Speed = 35kms/7kmph = 5hrs
Therefore, they will meet at 12pm.

Question 5 of 5
5. Question
Read the following passage and answer the questions that follow. Your answer to these questions should be based on passage only.
In the United States between 2001 and 2014, higher income was associated with greater longevity and differences in life expectancy across income groups increased over time. However, the association between life expectancy and income varied substantially across areas; differences in longevity across income groups decreased in some areas and increased in others. The differences in life expectancy were correlated with health behaviors and local area characteristics.
Apart from income, which of the following factors too contribute towards greater longevity and difference in life expectancy?
 Health behavior
 Local area characteristics
 Education qualification
Which of the following options are correct?
Correct
Solution (a)
There is no discussion about the role of education in the life span.
Incorrect
Solution (a)
There is no discussion about the role of education in the life span.
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