UPSC CSAT Quiz – 2021: IASbaba’s Daily CSAT Practice Test – 1st February 2021
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 Date February 1, 2021
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Daily CSAT Practice Test
Everyday 5 Questions from Aptitude, Logical Reasoning, and Reading Comprehension will be covered from Monday to Saturday.
Make the best use of the initiative. All the best!
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Question 1 of 5
1. Question
Find the sum of all 2digit numbers that gives a remainder of 3 when they are divided by 7
Correct
Solution (a)
The twodigit number which gives a remainder of 3 when divided by 7 are
10, 17, 24…….94
These number are in AP series with a = 10 and L = 94 with common difference d = 7
Number of terms n = 13
Sum = n*(a + L)/2
Sum = 13*52 = 676
Incorrect
Solution (a)
The twodigit number which gives a remainder of 3 when divided by 7 are
10, 17, 24…….94
These number are in AP series with a = 10 and L = 94 with common difference d = 7
Number of terms n = 13
Sum = n*(a + L)/2
Sum = 13*52 = 676

Question 2 of 5
2. Question
Find the missing number from the following pattern
Correct
Solution (b)
ColumnWise
(First Column Element * 2nd Column element) – (2nd column element) = Last Column Element
8×33=243=21
6×55=305=25
10×22=202=18
Incorrect
Solution (b)
ColumnWise
(First Column Element * 2nd Column element) – (2nd column element) = Last Column Element
8×33=243=21
6×55=305=25
10×22=202=18

Question 3 of 5
3. Question
The two numbers are in the ratio 3:4. If their LCM is 360, Find the smallest number?
Correct
Solution (c)
Let, these two numbers be 3X and 4X then their LCM = 12X.
Now, according to question,
12X = 360;
Or, X = 30;
Thus, the numbers are (3X = 3*30) = 0 and (4X= 4*30) = 120.
Then smaller in this two is 90.
Incorrect
Solution (c)
Let, these two numbers be 3X and 4X then their LCM = 12X.
Now, according to question,
12X = 360;
Or, X = 30;
Thus, the numbers are (3X = 3*30) = 0 and (4X= 4*30) = 120.
Then smaller in this two is 90.

Question 4 of 5
4. Question
There are 154 pearls in a necklace, and all are coloured either red or blue or green. The number of blue ones is three less than red and five more than green. Find the number of red pearls?
Correct
Solution (d)
Let the number of red pearls = X.
Hence, Blue pearls = (X3).
and Green pearls = (X8).
According to the sum,
X+X3+X8 = 154.
3X11 = 154.
X = 55.
Incorrect
Solution (d)
Let the number of red pearls = X.
Hence, Blue pearls = (X3).
and Green pearls = (X8).
According to the sum,
X+X3+X8 = 154.
3X11 = 154.
X = 55.

Question 5 of 5
5. Question
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. Find the ratio of their speed?
Correct
Solution (a)
Let the speeds of the two trains be X m/sec and Y m/sec respectively.
Then, length of the first train = 27X metres,
and length of the second train = 17Y metres.
27X+17Y/(X+Y) = 23
27X + 17Y = 23X + 23Y
4X = 6Y
Therefore, X/Y = 3/2
Incorrect
Solution (a)
Let the speeds of the two trains be X m/sec and Y m/sec respectively.
Then, length of the first train = 27X metres,
and length of the second train = 17Y metres.
27X+17Y/(X+Y) = 23
27X + 17Y = 23X + 23Y
4X = 6Y
Therefore, X/Y = 3/2